BRAINLIEST 6 points are placed on the line a 4 points are placed on the line b How many triangles is it possible to form such that their vertices will be the given points, if a is parallel to b?

all vertices on the two lines=60+36=96

Step-by-step explanation:

line a has 6 points and line b has 4 points

now each triangle drawn has on vertices on one line and two vertices on another line:

the line with six points :C(6,2) six points , has two vertices

C(6,2)=6*5/2*1=30/2=15 pairs of points

each pair connected to one point on the other line (4 points)

4*15=60 vertices

now let us consider the two lines on the other line with 4 points:

6c(4,2)=6*((4*3(/2))=6*6=36 vertices

all vertices on the two lines=60+36=96

5 + 8 +7 + 4 + 0 +1 = 25

step-by-step explanation: