In △ABC, AB=BC=29, and AC=42. What is the area of △ABC?

The area of △ABC is 420 square units.

The formula for calculating Heron's formula is expressed as √(s(s-a)(s-b)(s-c)  

where:

Get the value of "s"

s = (29+29+42)/ 2

s = 100/2

s = 50.

Get the required area:

Area = √50(50-29)(50-29(50-42)

Area = √176400

Area = 420.

Hence the area of △ABC is 420 square units.

Learn more on area of triangle here: link

420 unit^2.

Step-by-step explanation:

Use  the formula area = √(s(s-a)(s-b)(s-c)   where s = the semi-perimeter and ab and c are the 3 sides. (it is called Heron's Formula).

s = (29+29+42)/ 2

= 100/2

= 50.

Area = √50(50-29)(50-29(50-42)

= √176400

= 420.

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer

if i put something wrong your not gonna like it so rather not say nothing.