Samuel was given the diagram below and asked to prove that AC congruent BD. What would be the fifth step of the proof? Given: quadrilateral ABCD is a rectangle Prove: AC congruent BD A. bad = cda, using the sas congruence theorem B. abc = dac, using the aaa congruence theorem C. abd = acd, using the sss congruence theorem D. acb = cda, using the sas congruence theorem

The accompanying table shows the numbers of male and female students in a particular country who received bachelor's degrees in business in a recent year. complete parts (a) and (b) below. business degrees nonbusiness degrees total male 189131 634650 823781 female 169539 885329 1054868 total 358670 1519979 1878649 (a) find the probability that a randomly selected student is male, given that the student received a business degree. the probability that a randomly selected student is male, given that the student received a business degree, is nothing. (round to three decimal places as needed.) (b) find the probability that a randomly selected student received a business degree, given that the student is female. the probability that a randomly selected student received a business degree, given that the student is female, is nothing. (round to three decimal places as needed.)

Which property was used to simplify the expression? 3c+9 +4c=3c+4c+9

Opposite angles in a parrellelogram are