A region is bounded by semicircular arcs constructed on the side of a square whose sides measure 2/\pi, as shown. What is the perimeter of this region?

4

Step-by-step explanation:

The perimeter of the region is equal to the sum of the perimeter of the four semicircular arc. Since the semicircular arcs have the same measure, therefore:

Perimeter of region = 4 × Perimeter of semicircular arc.

The side of the square = diameter of the semicircle = 2/π.

The radius of semicircle = diameter/2 =

The perimeter of a semicircle = perimeter of a circle ÷ 2

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204