9) Find the equation of a mirror line to the points Q (1,2) and Q1 (-1,2)

x = 0

Step-by-step explanation:

Q(1, 2 ) and Q1(- 1, 2 ) are both 1 unit from the y- axis

Q is 1 unit to the right of the y- axis and Q1 is 1 unit is 1 unit to the left of the y-axis, thus

The y- axis is the mirror line with equation x = 0

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

15 batches are the most you can make

step-by-step explanation: