Tublu buys a cylindrical water tank of height 1.4m and diameter 1.1m to catch rainwater off his roof. He has a full 2 litres tin of paint in his store and decides to paint the tank (not the base). If he uses 250 ml to cover 1 2 , will he have enough paint to cover the tank with one layer of paint? [take = 3.142]

He will have enough paint to cover the tank with one layer of paint

Step-by-step explanation:

To calculate the area of the surface that has to be painted, we will have to calculate the lateral surface of the cylinder

Lateral surface of the cylinder is given by

A=2πrh

Where,

π=3.142

r=1.1/2m=

h=1.4m

A=2πrh

=2*3.142*1.1/2*1.4

=4.84m^2

He uses 250ml to cover 1m^2

To cover 4.84m^2, he will use

4.84m^2 × 250ml of paint

=1,210ml of paint is needed

He has 2 litres of paint

2litres =2000ml

Tublu has 2000ml of paint but needs 1210ml of paint

Therefore,

He has an excess of 2000-1210

=790ml

The answer is yes, he will have enough paint to cover the tank with one layer of paint.

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation: