In some year, two towns A and B had same population but after 10 years, population of A increased by 60% and of B decreased by
60%. What percent of A is the population of B?

The answer is 25%

Step-by-step explanation:

on the first year lets say town A and town B had a population of 100 (a town wouldn't have only 100 people but for simplicity lets do 100).

town A's population increases by 60%, 60% of 100 is 60, 100 + 60 = 160

town B's population decreases by 60%, 100 - 60 = 40

so now we have town A's population after 10 years and town B's population after 10 years, 160 divided by 40 = 4, and 100 divided by 4 equals 25, so the answer is 25%.

it’s supposed to be -4+45=41

step-by-step explanation:

b: |12 – x| ≤ 0.25

step-by-step explanation:      

let x be the possible lengths in inches, of the ribbons jaime cut.

we have been given that jaime is cutting strips of ribbon for a project. he tries to cut each piece to be 12 inches long, but sometimes he cuts it too long or too short by as much as 0.25 inch.  

we can represent this information in an inequality as:

by the definition of absolute value function we will get,

upon combining our inequalities we will get,

therefore, the inequality   describes all the possible lengths (x), in inches, of the ribbons jaime cut.

step-by-step explanation: