Find the first, fourth, and eighth terms of the sequence.
A(n) = -2x2^n-1

first term = -2

fourth term = -16

eighth term = -256

Step-by-step explanation:

Given;

A sequence with function;

A(n) = -2x2^(n-1)

The first, fourth, and eighth terms of the sequence can be calculated by substituting their corresponding values of n;

First term A(1); n = 1

A(1) = -2x2^(1-1) = -2×1 = -2

Fourth term A(4); n = 4

A(4) = -2x2^(4-1) = -2×8 = -16

Eighth term A(8); n = 8

A(8) = -2x2^(8-1) = -2×128 = -256

Therefore,

first term = -2

fourth term = -16

eighth term = -256

step-by-step explanation:

6.48/4 4 goes into 6.48 1.62 times

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier