Hurry hurry hurry hurry 50 points help plz help...it would be better if you have a picture..plz use steps Topic:copying a segment

Question:Copy PQ to the line with an endpoint at R

Question:This task will be complete when you have drawn an arc interesting the line to create a segment with length PQ

Our goal here is to create a copy of line segment PQ, through various steps. Let's start with drawing line segment PQ, respectively point R a fixed distance away from the segment.

It would be wise to use a compass in this case, and a ruler for certain.

So we have this segment PQ, and point R a " fixed distance " away from PQ.

( 1. Extend a compass to match with the length of PQ,

( 2. Move this compass ( without changing it's length ) so that one endpoint matches with point R

( 3. Now draw an arc with this compass, where this line will be

( 4. Take your ruler and draw a straight line from this point R to your arc. It would be wise to draw this line to the middle of the arc you created.

If you like, take a look at the attachment below to see what it should look like.

I have done these questions before, so I can assure you that this experiment is proved correctly!

left 3, up 4

step-by-step explanation:

just count the values of x & y of the vertex of the graph and see how many units in the x and y direction will get you from the f(x) graph to the f(x) graph

proofs involving isosceles triangles often require special consideration because an isosceles triangle has several distinct properties that do not apply to normal triangles.(more about triangle types) therefore, when you are trying to prove that two triangles are congruent, and one or both triangles, are isosceles you have a few theorems that you can use to make your life easier.

step-by-step explanation:

an isosceles triangle has two congruent sides and two congruent angles. the congruent angles are called the base angles and the other angle is known as the vertex angle. ∠bac and ∠bca are the base angles of the triangle picture on the left. the vertex angle is ∠abc