Find the axis of symmetry and vertex for the parabola y= -x²-6x+7

Step-by-step explanation:

y=-x²-6x+7

=-(x²+6x+3²-3²)+7

=-(x+3)²+9+7

=-(x+3)²+16

axis of symmetry is x+3=0 or x=-3

vertex=(-3,16)

Axis of Symmetry: -3

Vertex: (-3,16)

Step-by-step explanation:

To find the axis of symmetry in an equation of a parabola, you would use the formula x=-b/2a.

In this case, b is -6 and a is -1.

-(-6)/2*-1=-3

The axis of symmetry is -3 and also represents the x-coordinate of the vertex.

To find the y-coordinate of the vertex, you would plug in -3 to the equation so, it would be -(-3)^2-6*3+7=16.

Hence, we can say that the axis of symmetry is -3 and the vertex is (-3,16).

Hope this helps

just keep asking questions until you have a better understanding.

step-by-step explanation: