The deer population of a certain area is modeled by the formula: P=578e^0.045t where t is measured in years. In approximately how many years will the deer population reach 3000? 37.4 years 34.7 years 35.8 years 36.6 years

36.6 years

Step-by-step explanation:

Here, we are to find the number of years it will take for the population of deers to reach 3,000

What to do here is simply substitute the value of 3,000 for P and use it to find t

3000 = 578e^0.045t

Divide through by 578

5.1903 = e^0.045t

Take the ln (natural logarithm of both sides)

Recall ln e = 1

ln 5.1903 = ln e^0.045t

ln 5.1903 = 0.045t

0.045t = 1.6468

t = 1.6468/0.045

t = 36.595 years which is 36.6 years

the answer would be 484

step-by-step explanation:

just multiply 0.484 times 1,000 (formula)

b

step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b