Given: ∆KLM, KL ≅ LM A∈ KM , B ∈ KM AK ≅ BM Prove:△AKL ≅ △BML ΔALB is isosceles

ΔAKL is congruent to ΔBML by the Side Angle Side rule of congruency and ΔALB is isosceles as two of its sides and are congruent

Step-by-step explanation:

The given parameters are;

The given triangle ΔKLM has sides ≅ ,   Given

ΔKLM is isosceles Δ (two equal segments),         Definition of isosceles Δ

∠LKM ≅ ∠LMK,                                                       Base ∠s of isosceles Δ are ≅

Point A is on segment ,                                  Given    

Point B is also on segment ,                          Given

Segment ≅ segment ,                              Given

ΔAKL ≅ ΔBML,                                                       SAS rule of congruency

Segment ≅ segment ,                                CPCTC

ΔALB is isosceles (two equal segments),            Definition of isosceles Δ

Where:

SAS = Side Angle Side

CPCTC = Congruent parts of congruent triangles are congruent.

36/60

36/2=18

60/2=30

18/30

18/3=6

30/3=10

6/10

6/2=3

10/2=5

your final answer would be 3/5 of an

hope this !

chase is right because he already been to the swings and he know how far it will be to get there

step-by-step explanation: