Two circles have radii of 4 units and 6 units. What is the radius of a circle whose area is equal to the sum of the areas of the two given circles?

Step-by-step explanation:

We that the area of a circle is Pi times r^2 where r is the radius

Let A be the area of the first circle and S the area of the second one and T the total one

A=4^2× Pi

S=6^2× Pi

T = Pi( 4^2 +6^2)

= Pi ( 16+36) = Pi× 52

52 is the radius square

So r = root square 52 = 2 root square 13

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