As part of a new advertising campaign, a beverage company wants to increase the dimensions of their cans by a multiple of 1.12. If the cans are currently 12 cm tall, 6 cm in diameter, and have a volume of 339.12 cm3, how much more will the new cans hold? Use 3.14 for π and round your answer to the nearest hundredth. 476.44 cm3 137.32 cm3 815.56 cm3 379.81 cm3

B. 137.32 cm3

Step-by-step explanation:

So what we know is that

Height = 12

Diameter is 6 which would make the radius 3.

The current volume is 339.12

12cm × 1.12 = 12.44 (This is the new height.)

3cm × 1.12 = 3.36 9 (This is the new radius)

Volume of future can (V2) = πr²h = 3.14 × 3.36 ×3.36 × 13.44 = 476.43

Then you would subtract  476.43(new volume) - 339.12(old volume) = 137.31

That would round to 137.32 cm3.

So the answer is B. 137.32 cm3.

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb

d

step-by-step explanation: