A train slowed down from 50km/h to 10km/h in 2 minutes. How far did it travel in this time

S = 0.9 km

Step-by-step explanation:

Given:

Initial Velocity = = 50 km/hr = 13.89 m/s

Final Velocity = = 10 km/hr = 2.78 m/s

Time = t = 2 mins = 120 secs

Required:

Distance = S = ?

Solution:

Using 1st equation of motion:

=>

=> 2.78 = 13.89 + (a)(120)

=> 120a = 2.78 - 13.89

=> 120a = -11.11

Dividing both sides by 120

=> a = -0.1 m/s²

Now, Finding S by 2nd equation of motion:

S =

S = (13.89)(120)+1/2(-0.1)(120)^2

S = 1666.8 - 720

S = 946.8 metres

In kilometers

S = 0.9 km

the answer is d. 75%