Five years ago the age of father was twice as old as the age of daughter. The sum of present ages of the father and daughter is 55 years then find their present ages.

Step-by-step explanation:

Solution,

Five years ago,

Daughter's age = X - 5

Father's age = 2 ( X - 5 ) = 2x - 10

Present age,

Daughter's age = X years

Father's age = 2x - 5 years

According to Question,

X + 2x - 5 = 55

or, 3x - 5 = 55

or, 3x = 55+5

or, 3x = 60

or, X = 60/3

X = 20

The present age of daughter is 20

Again,

present age of father= 2x - 5

= 2* 20 - 5

= 40 - 5

= 35

Hope this helps...

Good luck on your assignment...

step-by-step explanation:

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !