Pl! A personal identification number (PIN) is a 4 digit code. A local bank only allows the numbers 1, 2, 3, 4, 5, 6, 7, 8, and 9 to be used. What is the probability that a randomly chosen PIN starts with 7 followed by 2 and doesn't contain the same number twice? Enter your answer as a fraction in simplest form.

14/2187

Step-by-step explanation:

Let us first see how many possible outcomes there are. We can to that by multiplying 9^4. This gives us 6561.

Now, we can see what are the possible outcomes that meet the requirements. We can get this by multiplying 1 • 1 • 7 • 6, which is 42.

Our fraction is 42/6561, which is 14/2187.

Hope this helped!

26 is 33.33% of 78

step-by-step explanation:

26 is what percent of 78?

26 is p% of 78

equation: y = p% * x

solving our equation for p

p% = y/x

p% = 26/78

p = 0.3333

convert decimal to percent:

p% = 0.3333 * 100 = 33.33%