Write the equation of a line that is perpendicular to -2/7x+9 that passes through the point (4, -6)

the desired equation is y = (-7/2)x - 8

Step-by-step explanation:

Don't you mean y = -2/7x+9, or y = (2/7)x+9?   Any line perpendicular to this line has a slope of -7/2, the negative reciprocal of (2/7).

Start with the slope-intercept formula:

y = mx + b.  Substitute -6 for  y, 4 for x and -7/2 for m.  Then we have

-6 = (-7/2)(4) + b.   This reduces to -6 = -14 + b, so that b must be -8.

Thus, the desired equation is y = (-7/2)x - 8

30 people weigh 160 pounds or more

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation: