Missing
number
write each
(5x3). + (n x4) =5X (3+4)
nx(5+3) = (6x5)+ (6 x3).
(4...
Mathematics, 16.07.2020 23:01 jokihahorton510
Missing
number
write each
(5x3). + (n x4) =5X (3+4)
nx(5+3) = (6x5)+ (6 x3).
(4х5)+4+2) = 4x C5 tn).
7x Cn+3)=(7+2)+7x3)
(6 x7) + Cnx4) = 5x (7+4)-
3x Cnts) 8+4 +6x5)
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