Y=-x^2-2x-5 whats the vertex of this parabola

The vertex is (-1, -4)

Step-by-step explanation:

Let's find the vertex by completing the square of y= -x^2 - 2x - 5.

Isolate the first two terms inside parentheses:       y= -(x^2 + 2x) - 5

Now complete the square of the expression inside these parentheses:

y = -(x^2 + 2x + 1 - 1) - 5

and rewrite this as

y = -(x + 1)^2 + 1 - 5, or

y = -(x + 1)^2 - 4

(x + 1) tells us that the x-coordinate of the vertex, h, is -1, and the -4 term tells us that the y-coordinate, k, is -4.  

The vertex is (-1, -4)