There are 125 people in a sport centre. 59 people use the gym. 70 people use the swimming pool. 55 people use the track. 25 people use the gym and the pool. 30 people use the pool and the track. 17 people use the gym and the track. 6 people use all three facilities. A person is selected at random. What is the probability that the person uses exactly one of the facilities? There are 125 people in a sport centre. 59 people use the gym. 70 people use the swimming pool. 55 people use the track. 25 people use the gym and the pool. 30 people use the pool and the track. 17 people use the gym and the track. 6 people use all three facilities. A person is selected at random. What is the probability that the person uses exactly one of the facilities?

Step-by-step explanation:

No of people using both gym and pool that is N( gup ) = 25

No of people using both track and pool that is N( tup ) = 30

No of people using both track and gym that is N( tug ) = 17

No of people using all that is N( gutup) = 6

No of people  using two or three facilities

= 25+30+17- 2 x 6

= 60

Total no of people = 125

No of people using only one facility

= 125 - 60

= 65 .

Ratio of people using only one facility

= 65 / 125

.52

Required probability

= .52 .

probability that the person uses exactly one of the facilities

= .52

yes

step-by-step explanation:

so of course you want to start by plugging the 5 in which goes to 7(5)+3(5)=50 because 7*5=35 and 3*5=15 and then add them together, then plug in the 5 to the other equation as well 9(5)+5=50 because 9*5= 45 and then add 5 and so yes they are equivalent.