HELP! Find the 11th term in the geometric sequence in which a3 is 24 and a5 is 96

a₁₁ = 6144

Step-by-step explanation:

The n th term of a geometric sequence is

= a₁

where a₁ is the first term and r the common ratio

Given a₃ = 24 and a₅ = 96 , then

a₁r² = 24 → (1)

a₁ = 96 → (2)

Divide (2) by (1)

= , that is

r² = 4 , thus

r = 2

substitute r = 2 into (1)

4a₁ = 24 ( divide both sides by 4 )

a₁ = 6

Thus

a₁₁ = 6 × = 6 × 1024 = 6144

i believe the answer to be 48

step-by-step explanation:

answer: at first, in 1635, the evening meetings had been just for women . .

what relationship between ideas is shown in the text above?

question 1 options:

location of events

similarity of events

timing of events

examples of an idea

step-by-step explanation: