If cote = and the terminal point determined by a is in quadrant 3, then: A. tang = 1
O B. csco = -
Lolo
DC. sing -
ml
O D. Cose =
3
5

The correct option is:

cosθ = -3/5

Step-by-step explanation:

We have been given that:

cotθ = 3/4

such that the terminal side of θ lies in III quadrant.

Consider it a right angled triangle.

We know that:

cotθ = Base / Perpendicular

Which means Base has a magnitude of 3 and Perpendicular has the magnitude of 4.

As It lies in III quadrant, both x and y are negative.

So

Base = -3

Perpendicular = -4

Find the hypotenuse by using Pythagoras Theorem

H² = (-3)² + (-4)²

H = 5

We know that:

cosθ = Base / Hypotenuse

cosθ = -3/5

the amount you'd have after the work is $1.55

step-by-step explanation:

you subtract 95% from $31.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: