I need to find a b and c please help

 a=4, b=16, c=12

Step-by-step explanation:

Use the intercept form: a(x - p)(x - q)  where p & q are the intercepts.

Given: p = -3, q = -1, and y-intercept (c) = 12

 a[x - (-3)][x - (-1)]

= a(x + 3)(x + 1)

= a(x² + 4x + 3)

= ax² + 4ax + 3a

y-intercept = 12

     3a = 12

       a = 4

   Substitute a = 4

    4x² + 4(4)x + 3(4)

=   4x² + 16x + 12

i dont know

step-by-step explanation: