What are the coordinates of point B on Line AC such that AB is 3 times as long as BC? (Screenshots supplied to clarify)

B(3.5, 0.5)

Step-by-step explanation:

Given:

A(5,5), Xa=5, Ya=5

C(3,-1), Xc=3, Yc=-1

To find point B, we can use the partition rule, where AB = 3BC, so AB occupies k=3/4 of the distance AC.

B(x,y) = ((1-k)Xa+kXc, (1-k)Ya+kYc)

=(Xa/4+3Xc/4, Ya/4+3Yc/4), substitute values

=(5/4+3*3/4, 5/4+3*(-1)/4)

=(14/4,2/4)

=(3.5, 0.5)

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

step-by-step explanation:

hjkj