An integer is three more than another integer. Twice the larger integer is two less than the square of the smaller integer. Find the two integers.

The integers are 4 and 7 or -2 and 1.

Step-by-step explanation:

You can make a system of equations with the description of the two integers.

1. x = y + 3

2. 2x + 2 = y^2

The simplest and the fastest way to solve this system in this case is substitution. You can substitute x for y + 3 in the second equation.

1. x = y + 3

2. 2(y + 3) + 2 = y^2

Now simplify and solve the second one. For convenience, I will just disregard the first equation for now.

2y + 6 + 2 = y^2

y^2 - 2y - 8 = 0

You can factor this equation to solve for y.

(y - 4) (y + 2) = 0

y = 4, y = -2

Now we can substitute the value of y for x in the first equation.

x = 7, x = 1

probably .5

i can on others if necessary.