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Mathematics, 15.07.2020 03:01 skywil8981

To evaluate the integral 0 (t1/3 βˆ’ t2/3) dt βˆ’1 , first use the property of definite integrals, that is, b (f(x) + g(x)) dx a = b f(x) dx a + b g(x) dx. a Therefore, 0 (t1/3 βˆ’ t2/3) dt βˆ’1 = 0 t1/ dt βˆ’1 ---Select--- 0 t /3 dt. βˆ’1

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To evaluate the integral 0 (t1/3 βˆ’ t2/3) dt βˆ’1 , first use the property of definite integrals, that...
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