Possible values for the area A of the rectangle shown are 12 ≤ A ≤ 36. Write and solve a compound inequality to find the possible values of x. Are these values all viable in this situation?I really need help

x can take any value and are viable in this situation if and only if it is a positive number

Step-by-step explanation:

We know that the area of a rectangle is given by:

A = x * y

So if we replace we have:

12 ≤ x * y ≤ 36

We divide by y, and we have:

12 / y ≤ x ≤ 36 / y

Which means that the value of x depends on y, that is to say if y is worth 1, the inequality would be:

 12 ≤ x ≤ 36

In the event that y is equal to 2:

 12/2 ≤ x ≤ 36/2

 6 ≤ x ≤ 18

Which means, that depending on y, x can take any value and are viable in this situation if and only if it is a positive number.

The image of the function is missing, you can see it at the end of the answer.

For a rectangle of length L and width W, the area is given by:

A = L*W

We will find that the solution is: 3/2 ≤ x ≤ 11/2

Here we have:

L = 3

W = 2x + 1

Then the area equation is:

A = 3*(2x + 1) = 6x + 3

And we also have the inequality:

12 ≤ A ≤ 36

Replacing A with the equation we get:

12 ≤ 6x + 3 ≤ 36

Now we solve this for x:

12 - 3 ≤ 6x ≤ 36 - 3

9  ≤ 6x  ≤ 33

Now we divide both sides by 6.

9/6 ≤ x ≤ 33/6

3/2 ≤ x ≤ 11/2

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