How would I figure this out?? pls explain.

D

Step-by-step explanation:

The diagonals of a rhombus bisect the angles, thus

∠ ABC = ∠ CBD = 5x - 18 and

∠ BAC = ∠ DAC = x

The diagonals are perpendicular bisectors of each other, thus

the angles round the intersection of the diagonals = 90°

Consider the triangle on the left of the rhombus, then

5x - 18 + x + 90 = 180 ( sum of angles in a triangle )

6x + 72 = 180 ( subtract 72 from both sides )

6x = 108 ( divide both sides by 6 )

x = 18 → D

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3