HELP?? A water tower is 52 feet tall and casts a shadow 78 feet long, while a child casts a shadow 6 feet long. How tall is the child?

Step-by-step explanation:

take a right triangle ABC...

right angled at B...

let AB be the height of the water tank...=52feet

AC hypotanuse...

BC is the length of the shadow..=78feet

tan thete=Opp/adj=AB/BC=52/78eq1

tan theta in both cases remain the same,

hence,

take a right triangle PQR...

right angled at Q...

let PQ be the height of the water tank...

PR hypotanuse...

QR is the length of the shadow...=6feet

tan theta=52/78 (from 1)

tan thete=Opp/adj=PQ/QR = PQ/6eq2

hence, from 1, 2

52/78=PQ/6

52x 6/78=PQ

52/13=PQ

Hence,4m=PQ=height of the boy...

Thank you, Hope this helps you dear friend

x + 4/7

step-by-step explanation:

use cymath

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!