With 98% confidence interval and n = 25. Find left critical value for Zinterval. 0 -2.492
0 -2.05
0 -2.797
-2.326

And , the degrees of freedom are given by:

Then the critical value using the t distribution with 24 degrees of freedom is:

And the best solution would be:

0 -2.492

Step-by-step explanation:

For this problem we know that the sample size is n = 25. The confidence level is 98% or 0.98 then the significance would be:

And , the degrees of freedom are given by:

Then the critical value using the t distribution with 24 degrees of freedom is:

And the best solution would be:

0 -2.492

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752