I will give brainliest to simplest explanation! There are 2 Senators from each of 50 states. We wish to make a 3-Senator committee in which no two members are from the same state. How many ways can the 3-Senator committee be formed such that no two Senators are from the same state?

117,600 ways

Step-by-step explanation:

This problem can be solved using fundamental principle of counting , according to which , if there are m different things and n different things,

then there m*n ways to combine.

Example: if there 5 shirts and 3 ties,

then number of ways in which different combination shirt and tie can be worn is

5*3 = 15 ways.

In the problem,\

number of states is 50,

let those states be

A1, A2, A3, A4 A50

in each state there are 2 senate

Condition

3-Senator committee in which no two members are from the same state.

then

first member can be chosen from any of the 50 state,

hence first member can be chosen in 50 ways

for simplicity lets take state A1, you can choose any one you wish

second member cannot be from state A1, then number of state left = 49

second member can be chosen from  any of 49 state left

hence second member can be chosen in 49 ways

for simplicity lets take state A2,

Third member cannot be from state A1 and A2, then number of state left = 48

Third member can be chosen from  any of 48 state left

hence Third member can be chosen in 48 ways

for simplicity lets take state A3,

Hence no. of ways of choosing  3-Senator committee be formed such that no two Senators are from the same state = 50*49*48 = 117,600 ways

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted