if (ax+b)(ax+c)=4x^2-25 for all values of x, and a, b, and c are constants, what is the value of b+c?

10.

Step-by-step explanation:

You are given the equation

(ax+b)(ax+c)=4x^2-25

Expand the Left hand side by opening the bracket.

a^2x^2 + axc + abx + bc

a^2x^2 + (axc + abx) + bc = 4x^2 + 0x - 25

From the equation above, we can see that;

a^2x^2 = 4x^2

a^2 = 4

a =  √4

a = 2

Also, axc + abx = 0x

axc = abx

ax will cancel out from both sides

c = b

From the equation, bc = 25

But c = b. Substitute c for b

b^2 = 25

b =  √25

b = 5 = c

b + c is therefore 5 + 5 = 10

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step-by-step explanation:

dhwidjajxvahhzabduqhdb

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".