Can someone please help me with this questions. They are quadratic graphs you don't necessarily have to plot the graph. Help me to find y

See below in bold.

Step-by-step explanation:

y = x^2 + 3x - 1.

You find the values of y by substituting the individual values of x.

So when x =- -4,  y = (-4)^2 + 3(-4) - 1

= 16 - 12 - 1

= 3.

When x = -3, y = (-3)^2 + 3(-3) - 1 = 9 - 9 - 1

= -1.

When x = -2, y = 4 - 6 - 1 = -3.

When x = -1, y = 1 -3 - 1 = -3.

When x = 0, y =  0 - 0 - 1 = -1.

When x = 1, y = 1 + 3 - 1 = 3.

the answer to the expression is 83

w'x is 0.

hope it