The length of a rectangle is 11 yds more than twice the width, and the area of the rectangle is 63 yd ^2, find the dimentions of the rectangle

Step-by-step explanation:

Area of a rectangle = l × w

where l is the length

w is the width

length of a rectangle is 11 yds more than twice the width is written as

l = 11 + 2w

Area = 63 yd²

(11+2w)w = 63

2w² + 11w - 63 = 0

Solve the quadratic equation

( w + 9) ( 2x - 7) = 0

w = - 9 w = 7/2 or 3.5

Since width is always positive w is 3.5 yd

l = 11 + 2(3.5)

l = 11 + 7

l = 18 yd

The length is 18 yd

The length is 18 ydThe width is 3.5 yd

Hope this helps you

horizontal translation of 2 units in the positive x direction

followed by

vertical translation of 3 units in the positive y direction

i think there was a typo. you wrote pat brings 3 quarts of ice-cream to the party. each serving of ice-cream is 1 6 quart. how many total servings of ice-cream does pat bring to the party? i think the bold is supposed to be 1/6. so 1 quart of ice cream = 6 servings. 6 * 3 = 18.