The side length of a square is represented by x centimeters. The length of a rectangle is 3 cm greater than the side length of a square. The width of the rectangle is 3 cm less than the side length of the square. Which figure has the greater area and by how much?

The square has a greater area having an area of 9 cm more than that of the rectangle.

Step-by-step explanation:

Length of square = x

Length of rectangle = 3+x

Width of rectangle = x-3

Area of square:

=>

=> x × x

=> x²

Area of Rectangle:

=>

=> (3+x)(x-3)

Using FOIL

=> 3x-9+x²-3x

=> x²-9

From the above calculations, we come to know that the square has a greater area having an area of 9 cm more than that of the rectangle.

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5

the ratio of white tiles to blue tiles is 48: 16. the ratio in it's simplest form is 3: 1.

step-by-step explanation:

ratio: take the first number and add a colon next to it, then add the second number after that. make sure the ratio order matches up with the written problem!

simplest form: we can simplify the ratio 48 : 16 by dividing both terms by the greatest common factor (gcf).

the gcf of 48 and 16 is 16.

divide both terms by 16:

48 ÷ 16 = 3

16 ÷ 16 = 1

reducing to simplest form:

48 : 16 = 3 : 1