Find the zeros of y = x2 - 6x - 4 by completing the square. A. x=-34/13
B. X- 3+ 118
CX13
D. x 316

x = 3 ±

Step-by-step explanation:

Given

y = x² - 6x - 4

To find the zeros let y = 0, that is

x² - 6x - 4 = 0 ( add 4 to both sides )

x² - 6x = 4

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- 3)x + 9 = 4 + 9 , that is

(x - 3)² = 13 ( take the square root of both sides )

x - 3 = ± ( add 3 to both sides )

x = 3 ± ← exact solutions

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