Find a missing numerators in each of the following problems. a. 10/15 = /60 b. /180 = 4 / 9 c. 7/11 = /121 d. /144 = 2/6

  a) 40

  b) 80

  c) 77

  d) 48

Step-by-step explanation:

To find the missing numerator, multiply the equation by the denominator of the fraction with the missing numerator.

a) (10/15)(60) = (x/60)(60)

  40 = x

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b) (x/180)(180) = (4/9)(180)

  x = 80

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c) (7/11)(121) = (x/121)(121)

  77 = x

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d) (x/144)(144) = (2/6)(144)

  x = 48

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.