A researcher records the amount of time (in minutes) that parent child pairs spend on social networking sites to test whether they show any generational differences. From the following findings in APA format, interpret these results by stating the research design used (repeated measures or matched pairs), the sample size, the decision, and the effect size. Parents spend significantly less time on social networking sites compared their children (MD = -42 minutes),t(29)=4.021,p<.05,d=0.4 9.(a) What research design was used? (Repeated measures or matched pairs?)(b) What is the sample size? (n = ?)

(a) matched pair design

(b) n = 30

(c) Reject the null hypothesis.

Step-by-step explanation:

The complete question is:

A researcher records the amount of time (in minutes) that parent child pairs spend on social networking sites to test whether they show any generational differences. From the following findings in APA format, interpret these results by stating the research design used (repeated measures or matched pairs), the sample size, the decision, and the effect size. Parents spend significantly less time on social networking sites compared their children (MD = -42 minutes),t(29)=4.021,p<.05,d=0.49.(a) What research design was used? (Repeated measures or matched pairs?)(b) What is the sample size? (n = ?)(c) What is the decision? (Retain or reject the null?)

Solution:

(a)

It s provided that the researcher records the amount of time (in minutes) that parent-child pairs spend on social networking sites.

This implies that the data collected is in the form of paired data.

Thus, the research design that was used was matched pair design.

(b)

Consider the t-statistics provided:

t (29) = 4.021

The number 29 in the bracket is the degrees of freedom.

The degrees of freedom for a matched pair design is,

df = n - 1

Compute the value of n as follows:

df = n - 1

29 = n - 1

n = 29 + 1

n = 30

Thus, the sample size is n = 30.

(c)

The p-value of the test is:

p < 0.05

The p-value of the test is less than the 5% significance level.

This implies that the null hypothesis will be rejected at 5% significance level.

idk

step-by-step explanation:

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.