(Please help I suck at geometry!) Write an equation of a line perpendicular to line AB below in slope-intercept form that passes through the point (7, 6). Line AB is shown. A is at 0, 1. B is at negative 2, 5. (6 points) y = 0.5x + 2.5 y = 0.5x − 2.5 y = −2x + 20 y = 2x − 20

y = 1/2x + 5/2

P.S, this isn't geometry really. It's more like algebra :)

Step-by-step explanation:

Step 1: Find equation of line AB

m = (5 - 1)/(-2 - 0)

m = 4/-2

m = -2

y = -2x + 1

Step 2: Find slope of perpendicular line

Take the negative reciprocal of line AB

m = 1/2

y = 1/2x + b

Step 3: Find b

6 = 1/2(7) + b

6 = 7/2 + b

b = 5/2

Step 4: Rewrite perpendicular equation

y = 1/2x + 5/2

or

y = 0.5x + 2.5

y = 1/2x + 5/2 or y = 0.5x + 2.5

Step-by-step explanation:

c. 65°

step-by-step explanation:

we are given a triangle with two known angles, 62° and 53°, while the third angle x is unknown and we are to find its value.

we know that the sum of angles in a triangle is equal to a total of 180 degrees. so we can write it as:

x + 62° + 53° = 180°

solving to find the value of x:

x = 180 - (62 + 53) = 65°

therefore, the value of x in this triangle is 65°.

cut 138 centimeters off

step-by-step explanation:

250-112 = 138