PLEASE HELP!!(PIC INCLUDED) Which of the following steps were applied to ABCD to obtain A'B'C'D?

A. shifted 3 units right and 2 units down

B. shifted 4 units right and 2 units down

C. shifted 2 units right and 3 units down

D. shifted 3 units right and 1 unit down

A. Shifted 3 unit right and 2 unit down

Step-by-step explanation:

Let's determine the reason for the answer.

We will use a reference point, only one point to determine the reason.

Because the both shape are identical.

Let's use point A

The position of A is 2 on the y axis and 1 on the x axis

While the position of A' is 0 on the y axis and 4 on the X asis

Let's know how many units where moved from the position.

A' -A

For X axis

4-1= 3

For y axis

0-2= 2(we need only the magnitude)

So its 2 units Down and 3 unit right

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

56

step-by-step explanation: