Let the mean of the population be 38 instances of from 6" - 9" hatchings per nest, and let the standard deviation of the mean be 3. What sample mean would have a confidence level of 95% or a 2.5% margin of error?

Mean of the population having 6"-9" Hatching =38

Standard Deviation =4

Step-by-step explanation:

Confidence interval of 95% means that 95% of data lie within two standard deviations.

That is data values lie between 38-2×4 to 38 +2×4.

⇒Which is 38-8 to 38+8.

⇒30 to 46.

it is also given that margin of error is 2.5%.

So, the data value will lie between

Mean of beginning value to extreme value of 95% confidence level

So, Sample mean of this observation having 2.5% margin of error = 38

Option D:→ 38

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.

s

step-by-step explanation: