I NEED HELP PLEASE THANKS! :) Find the seventh partial sum of 13, 22, 31, 40, ... 9
67
106
280

Step-by-step explanation:

Arithmetic sequence

First term a = 13

Common difference = 2nd term - first term

                                 = 22 - 13

                             d = 9

   = 13 + 54

  = 67

Sum of 7 terms =

                         =

                         =

                          =

                         = 7 *40

                          = 280

m∠abd = m∠dbc

step-by-step explanation:

given : ab bisects ∠dbc

as we know that bisection means ab divides   ∠dbc   in two equal angles named as   ∠dba and   ∠abc

so, m∠abd = m∠dbc  

because ab bisects ∠dbc.

hence , the first statement m∠abd = m∠dbc is true.

the anwser is x< -17/2