If triangle ABC has the following measurements, find the measure of side c.
a = 10
b = 3
C = 15°
(Hint: c^2 = a^2 +b^2 - 2ab*cos(C) is law of
cosine)

Measure of side C is 7.14

Step-by-step explanation:

In this question, we are to find the length of the side C.

To get this, we are to employ the use of the cosine formula.

Mathematically, this is calculated as;

c^2 = a^2 +b^2 - 2ab*cos(C)

Where; a = 10 b = 3 and c = 15 degrees

Plugging these values into the equation, we have;

C^2 = 10^3 + 3^2 -2(3)(10)Cos 15

C^2 = 100 + 9 - 57.96

C^2 = 51.04

C = √(51.04)

C = 7.14

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square