a safe has a 4-digit lock code that does not include zero as a digit and no digit is repeated. What is the probability that the lock code consists of all even didgits?

Step-by-step explanation:

9 all possible digits (1, 2, 3, 3, 4, 5, 6, 7, 8, 9)

4 digits and no digits repeated so

9•8•7•6      - number of all possible codes

4 even digits (2, 4, 6, 8)

4 digits and no digits repeated so

4•3•2•1       - number of all codes wich consists of all even digits

What is the probability that the lock code consists of all even didgit:

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-2

7 - 9 = -2

reversed:

-2 + 9 = 7