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a. A/B = 7/3

b. (p,q) = (4,0)

c. (p,q) = (0,2)

Step-by-step explanation:

We have the line as:

21x-6y-15 = 0

The general form of the equation of a straight line is;

y = mx + c

Where m is the slope and c is the y -intercept

writing the above in this manner, we have

6y = 21x -15

Now let’s divide through by 6;

y = 21x/6 -15/6

y = 7x/3 -5/3

Since in the general equation of a straight line, the coefficient of x is the slope, this means that our slope is 7/3 which makes A = 7 and B = 3

Considering the equation;

3x + 6y = 12

Expressing in the general form, we have

6y = 12-3x

divide through by 6

y = 12/6 -3x/6

y = 2-0.5x

Now we want to find the x intercept. At the x-intercept, the value of y = 0

Thus 0 = 2-0.5x

0.5x = 2

x = 2/0.5 = 4

so (p,q) = (4,0)

For the y intercept

y = 2-0.5x

Obviously the y intercept here is 2, so the coordinates of the y-intercept here is (0,2) = (p,q)

what's the question?

step-by-step explanation:

there is no question.

1. sometimes

2. never true

3. sometimes

step-by-step explanation:

these are pretty self explanatory if you know what supp right and com angles are