Students in four of Ms. Peters’s classes were surveyed about their favorite type of movie. The results are as follows: Class 1: Action - 12, Comedy - 13, Drama - 6 Class 2: Action - 9, Comedy - 11, Drama - 11 Class 3: Action - 8, Comedy - 15, Drama - 7 Class 4: Action - 11, Comedy - 4, Drama - 18 8. Create a two-way table to organize the data. 9. What is the probability that a randomly selected student in Ms. Peters’s first class prefers comedies? 10. What is the probability that a randomly selected student is in Ms. Peters’s second class or prefers action movies?

(a) Refer to picture attached

(b) Probability that randomly selected student in class 1 prefers comedies is 42%

(c) Probability that randomly selected student in class 2 prefers action movies is 29%

Step-by-step explanation: Please refer to the picture attached for the required two-way table.

For the first class, that is class 1, you need to calculate the probability that a randomly selected student prefers comedies. A probability can be expressed as follows;

P(comedies) = Number of required events / Number of possible outcomes

P(comedies) = 13/31

P(comedies) = 0.419354

Therefore the probability that a student selected randomly from Ms Peter's first class prefers comedies is 0.4193 (approximately 0.42) or 42%.

For the second class, that is class 2, you need to calculate the probability that a randomly selected student prefers action movies. The probability thus is expressed as;

P(Action) = Number of required events / Number of possible outcomes

P(Action) = 9/31

P(Action) = 0.290322

Therefore the probability that a student randomly selected from Ms Peter's second class prefers action movies is approximately 0.29 or 29%.

false

step-by-step explanation:

4y - 6 + 4y^2 - 9

before simplifying this contains 4 terms

after simplifying

4y -15 + 4y^2

it contains 3 terms

i’m here for points.