I NEED HELP PLEASE, THANKS! :) A commercial passenger jet is flying with an airspeed of 185 miles per hour on a heading of 036°. If a 47-mile-per-hour wind is blowing from a true heading of 120°, determine the velocity and direction of the jet relative to the ground. 186.1 mph, 021° 188.5 mph, 021° 195.6 mph, 069° 186.1 mph, 069°

We are given that the passenger's jet is flying at a speed of 185 miles per hour, with a direction of 36 degrees, and the wind speed being 47 mph with a direction of 120 degrees. From this, you could create a diagram is shown in the attachment.

[ 185 cos 36, 185 sin 36 ]

+ [ 47 cos 120, 47 sin 120 ]

[ 185 cos 36 + 47 cos 120, 185 sin 36 + 47 sin 120 ]

√( 4263  + 33988 )^2

= ( About ) √38251 = 195.57 mph

Solution = 195.6 mph, 069°

step-by-step explanation:

b and c