Hi please dont do an explination just the answer

a.) Jupiter

b.) radius of Mercury is 2440km

c.) The difference is 1.33*10^27kg

Hope this helps you

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

false

step-by-step explanation: