1) -2q-5= -11 2)3(8+k) = 33 3)4/6=x/9 4)6(y+3)=24 5)4k+8=26 6)8y=6+2y 7)3x-7=20 pls help

1) -2q-5= -11

-2q = -11+5

q = -6/-2 =3

2) 3(8+k) = 33

24 + 3k = 33

3k = 33-24

K = 9/3 = 3

3) 4/6=x/9

By cross multiplication

4x9 = Xx6

36 = 6x

So, x = 6

4) 6(y+3)=24

6y + 18 = 24

y = (24-18)/6 = 1

5)4k+8=26

4k = 26-8

k = 18/4 = 4.50

6)8y=6+2y

8y - 2y = 6

6y = 6

So, y = 1

7)3x-7=20

3x = 20+7

x = 27/3 = 9

sites:

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.